Question

Ifp=HCF(100,190)and q=LCM(100,190),then find p2q2

Answer 1

Answer:

$p^2q^2=361000000$

Step-by-step explanation:

Formula used:

Product of two numbers = product of their HCF and LCM

Given numbers are 100 and 190

Given:

$p=HCF(100,190)$

$q=LCM(100,190)$

By the given formula, we get

$p*q=100*190$

$pq=19000$

Now,

$p^2q^2$

$=(pq)^2$

$=(19000)^2$

$=361000000$

Answer 2

Solution:

If
p=HCF(100,190)

$100 = 2 \times 2 \times 5 \times 5 \\ \\ 190 = 2 \times 5 \times 19$
$p = 2 \times 5 \\ \\ p = 10$
q=LCM(100,190)

$q = {2}^{2} \times {5}^{2} \times 19 \\ \\ q = 4 \times 25 \times 19 \\ \\ q = 1900$
Now

${p}^{2} {q}^{2} = ( {10)}^{2} \times ( {1900)}^{2} \\ \\ = > 100 \times 3610000 \\ \\ {p}^{2} {q}^{2} = > \: 361000000$