Question

ifp(x) =x^2- 2√2x then p(2√2) is equal to _______________ .​

Answer 1

Answer:

answer is 0

Step-by-step explanation:

hope help you mate

Answer 2

Answer:

The value of p (2√2) is 0.

Step-by-step explanation:

The expression of p (x) is:

$p(x)=x^{2}-2\sqrt{2}x$

For x = 2√2 compute the value of p (2√2) as follows:

$p(x)=x^{2}-2\sqrt{2}x\\=(2\sqrt{2})^{2}-(2\sqrt{2})\times(2\sqrt{2})\\=(2\sqrt{2})^{2}-(2\sqrt{2})^{2}\\=0$

Thus, the value of p (2√2) is 0.