Question

ifp(x)=x^3-3x^2+3x-4 find p(2)+p(-2)+p(0)​

Answer 1

Answer:

$p(x) = {x}^{3} - 3 {x}^{2} + 3x - 4$

First of all we find p(2)

So, p(2)=(2)³-3(2)²+3(2)-4

= 8-12+6-4

= - 2

Now,

p(-2) = (-2)³-3(-2)²+3(-2)-4

= -8 -12 - 6 - 4

= - 30

Now,

p(0) = 0 - 0 + 0 - 4

= - 4

So, p(2) + p(-2) + p(0)

= - 2 - 30 - 4

= - 36

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