Ifp(x)=x²-4x+4,then find the value of p(2)+p(-2)+p(1)
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Answered by
3
Answer:
heya mate there's your answer
p(x)=x^2-4x+4
Now, p(1)=(1)^2-4(1)+4
=1-4+4
p(1)=1
p(2)=(2)^2-4(2)+4
=4-8+4
= 8-8
=0
p(-2)=(-2)^2-4(-2)+4
=4+8+4
=16
now,p(2)+p(-2)+p(1)=0+16+1
=17
hope it helps you
Thank you
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