Question

Ifr=-2ys = 3 - 2x - 2y, t = -2x then the nature of function at
stationary point (1,1) is​

Answer 1

Answer:  Ifr=-2ys = 3 - 2x - 2y, t = -2x then the nature of function at stationary point (1,1)

Step-by-step explanation:

Answer 2

Answer:

The function has maximum value at (1, 1)

Step-by-step explanation:

Here it is given that r = -2y , s = 3 - 2x -2y, t = -2x at (1, 1)

r = -2y = -2(1) = -2

s = 3 - 2x -2y = 3 - 2(1) - 2(1) = 3 - 2 -2 = 3 -4 = -1

t = -2x = -2(1) = -2

We know that, a function f(x, y) is said to have extremum value at (a, b) if rt - s² > 0 and r < 0

Now rt - s² = (-2)(-2) - (-1)² = 4 - 1 = 3 > 0 also r < 0

So the function has maximum value at (1, 1)