Ifroot3 tan Rita=1 find the value of sin square therapy -coz square theta
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root3 tan theta = 1
tan theta = 1/root3
tan theta = tan 30 since 1/root 3= tan 30
therefore theta= 30
now
sin square 30 - cos square 30
= (1/2)^2 - (root3/2)^2
= 1/4 - 3/4
= -2/4 = -1/2.
tan theta = 1/root3
tan theta = tan 30 since 1/root 3= tan 30
therefore theta= 30
now
sin square 30 - cos square 30
= (1/2)^2 - (root3/2)^2
= 1/4 - 3/4
= -2/4 = -1/2.
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