ifthe 10th term of an AP is 47 and its first term is 2 find the sum ofits 15 term
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A+9D=47
A=2
SO,
2+9D=47
9D=45
D=5
NOW,
SUM OF THE 15 TERMS =N/2(2A+(N-1)D)
=15/2(4+70)
=15/2 (37)
THEREFORE,S15=555
A=2
SO,
2+9D=47
9D=45
D=5
NOW,
SUM OF THE 15 TERMS =N/2(2A+(N-1)D)
=15/2(4+70)
=15/2 (37)
THEREFORE,S15=555
Answered by
0
I have worked out the sum in the attachment given below. hope it helps you.
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