Math, asked by prashantparate04, 28 days ago

Ifthe circumference of acircular sheet is 154 m . Find its radius . Also find the area of the sheet take 22 by seven​

Answers

Answered by veer6634
1

Circumference = 2πr

so , 2 × 22/7 × r = 154

r = 154 × 7 / 44

r = 1078 / 44

r = 49 m

Now are of sheet = πr^2

= 22 / 7 × 49 × 49

= 7546 m^2

Answered by amna3961
94

  \large\underline {\maltese{ \textsf {\textbf{ \: Question:}}}}

If the Circumference Of a circular sheet is 154 m . Find its Radius . Also find the area of the sheet by taking π ≈ 22/7.

 \large{\underline{\maltese{\textsf {\textbf {  \: Answer:}}}}}

 \large\mathfrak{ \dag  \: Given: }

 \small \bullet \sf  \: \: Circumference \: of \: a \: circle \:  = 154 \: m

  \small\bullet \sf  \: Value \: of \:  \pi \:   \approx \:  \frac{22}{7}

  \large\mathfrak{ \: \:  \dag \: To \: Find \:  Out : }

 \small \bullet \sf \:  \: Radius \: Of \: a \:  \bold {circular \: sheet \: } \:

 \bullet \small \sf  \: \:  Area \: of \: a \:  \bold{ \: circular \: sheet}

   \large\mathfrak{\dag \: Required \: Formulas : }

 \longrightarrow \:  \sf \: Radius \:  =   \bold{\frac{C}{2 \pi} }

 \longrightarrow \: \sf \: Area \:  =  \bold{ \:  \pi \:  {r}^{2} }

  \large\star \: \underline{ \underline{ \sf  by \: using \: formula \: radius \: of \: a \: circular \: sheet : }}

   \small \implies\sf \: Radius \:  =  \frac{C}{2 \pi}

  \small\implies \sf \: Radius \:  =  \frac{154 \times 7}{2 \times 22}

  \small\implies \sf Radius \:  =  \frac {\cancel{1078}} {\cancel{44}}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \therefore\boxed  {\underline {\mathfrak{ \red{  Radius \:  = 24.5 \: m}}}} \:  \:  \:  \:  \:  \:  \:  \:

  \large\star \sf \: { \underline {\underline by \: using \: a \: formula \: area \: of \: a \:  \bold { \: circular \: sheet: }}}

 \small \implies \sf \: Area \:  =  \pi \:  {r}^{2}

 \small \implies \sf \:Area \:  =  \frac{22}{7}  \times 24.5 \times 24.5 \:  \:

 \small \implies  \sf \: Area \:  =  \frac{22}{ \cancel{7}}  \times { \cancel{600.25}}

 \small \implies \sf \:Area \:  = 22 \:  \times 85.75

  \:  \:  \:  \:  \: \:  \:  \:   \:  \:  \:  \:  \therefore \: \boxed {\underline { \mathfrak{ \red{ \: Area \:  = 1886.5 {cm}^{2} }}}} \:  \:  \:  \:  \:

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~@amna3961 ♡︎ ✔︎

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