Question

Ifthe point (3, 4) lies on the graph ofthe equation 3y = ax + 7, find the value of a.

Answer 1

Given that : ( 3 , 4) =( x , y )
putting values in equation
3y = ax + 7
3(4) = a(3) +7
12 = 3a + 7
12- 7 = 3a
3a = 5
a = 5/3

Answer 2

Answer:

a=5/3

Step-by-step explanation:

If the point (x1.y1) lies on a straight line with equation ax+by+c =0, then the point must satisfy the equation, i.e. ax1+by1+c=0.

So, in our problem (3,4) point lies on the graph of the straight line 3y=ax+7. So, this given equation must be satisfied by the point.

Hence, putting x=3 and y=4 in the given equation we get,

3(4)=3a+7, ⇒3a=12-7 =5, ⇒ a= 5/3. (answer)