Question

Ifthesumofthezeroesofthequadraticpolynomial3x2–kx+6is3,thenfind
thevalueofk.

Answer 1

Step-by-step explanation:

Given

$sum( \alpha + \beta ) = 3$

$3 {x}^{2} - kx + 6x$

We know that.

$\alpha + \beta = \frac{ - b}{a}$

$3 = \frac{k}{3}$

$k = 9$

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Answer 2

${\large{\sf{\green{Required \: \: Answer}}}}</p><p>$

Given:

3x² - kx + 6 = 3, k = ?

Answer:

a = 3

b = -k

c = 6

WKT,

Sum of Zeroes is : -b / a

Here, The Sum is : 3

So,

$\frac{ - b}{a} = 3 \\ \\ \frac { - ( - k)}{3} = 3 \\ \\ \frac{k}{ 3} = 3 \\ \\ k = 3 \times 3 \\ \\ { \boxed{ \color{orchid}{k = 9}}}$

HOPE IT HELPS !