Iftwo zeroes of the polynomial x 3 -4x 2 -3x+12 are root 3 and -root 3
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If two zeroes are √3 and -√3
so, the factor will be
(x-√3)(x+√3) =0
⇒x²-3=0
now, dividing the expression with this,
x²-3)x³-4x²-3x+12( x-4
x³ -3x
- +
-4x²+12
-4x²+12
+ -
0 0
so,x³-4x²-3x+12 = (x²-3)(x-4)
so, the factor will be
(x-√3)(x+√3) =0
⇒x²-3=0
now, dividing the expression with this,
x²-3)x³-4x²-3x+12( x-4
x³ -3x
- +
-4x²+12
-4x²+12
+ -
0 0
so,x³-4x²-3x+12 = (x²-3)(x-4)
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