Math, asked by nandakrishiv2608, 1 month ago

Ifx= 1/12−√3Prove that x²-4x+1=0

Answers

Answered by poojatagra662
2

Answer:

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Answered by ITZURADITYAKING
2

Answer:

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I know three methods...

Step-by-step explanation:

Method 1)

Checking if x=2+\sqrt{3}x=2+3 is true for x^2-4x+1=0x2−4x+1=0 .

\begin{gathered}(2+\sqrt{3} )^2-4(2+\sqrt{3} )+1\\=7+4\sqrt{3} -8-4\sqrt{3} +1\\=0\end{gathered}(2+3)2−4(2+3)+1=7+43−8−43+1=0

∴x=2+\sqrt{3}x=2+3 (True)

Method 2)

Using Quadratic Formula

\begin{gathered}x=\frac{4\frac{+}{}\sqrt{16-4} }{2} \\\end{gathered}x=24+16−4

∴x=2\frac{+}{} \sqrt{3}x=2+3 (True)

Method 3)

Making Quadratic Equation from Root

(ii ) Move xx and rationals to the left hand side.

(iiii ) Leave square roots on the right hand side.

(The root and conjugate root is its roots.)

x-2=\sqrt{3}x−2=3

x^2-4x+4=3x2−4x+4=3

∴x^2-4x+1=0x2−4x+1=0 (True)

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