Question

ifx+1\x=4 find the value of x^3+1\x^3​

Answer 1

Answer:

x^3 + 1/x^3 = (X+1/X)^3 -3 (X+1/X)= (4)^3 -3 *4

64-12

52

Answer 2

Answer:

${ (x + \frac{1}{x} ) }^{3} = {x}^{3} + { \frac{1}{x} }^{3} + 3x + \frac{3}{x}$

${x}^{3} + { \frac{1}{x} }^{3} = {4}^{3} - 3(x + \frac{1}{x} )$

${x}^{3} + { \frac{1}{x} }^{3} = 64 - 12$

${x}^{3} + { \frac{1}{x} }^{3} = 52$

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