Question

Ifx^11 + 101 is divided by x+1 then what remainder do we get

Answer 1

Hello

We can solve this using the remainder theorem


p(x)=x¹¹+101
g(x)=x+1
First we shall find the zero of g(x)
x+1=0
x=-1

Substituting the value of x in p(x)

p(-1)=(-1)¹¹+101
As -1 is raised to an odd power -1¹¹= -1
p(-1)=-1+101=100

So the remainder is 100.
Hope it helps.

Answer 2

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