Math, asked by siyaparv, 19 hours ago

Ifx=3, y=-4, z=-7
Verify: xx(y+z)=(xxy)+(x×z)
Write also the name of the property used.
(Hint: Solve L.H.S and R.H.S, Compare)


plz tell the ones who will tell correct i will mark him or her as brainliest

Answers

Answered by shivusin703
0

Answer:

Proof for x+y=x+y

Simply you can substitute the values of x&y and can prove it.

LHS=x+y

=3/7 +5/4

=47/28

RHS=x+y

=3/7+5/4

=47/28

, but with these kind of equations, you can never be sure!

Simply by the laws of equations, (Sorry I can’t remember the name!) your goal is to isolate the x and the y variables as much as possible. Therefore, the order of operations states exponents come first with the last numbers.

(2x-y)^2=(2x-y)(2x-y)

This is actually quite similar to FOIL, which I enjoyed learning! 2x * 2x = (4x)(4x)=16x(x). Right now, we have 16x(x). Now, we have to multiply “-y and

How do you verify x+y=y+x for the following values of x and y, x= 5/7y,=-3/2?

L.H.S.=x+y= 5/7+ (-3/2)

=5/7 - 3/2

[Adding any number to a negative number results in subtraction between the two numbers

When you add a positive number, you move to the right on the number line.

When you add a negative number, you move to the left on the number line.]

Hence, x+y =10/14 - 21/14 [Taking L.C.M within the denominators]

x+y = -11/14

Similarly,

R.H.S.=y+x= (-3/2) + 5/7

=-21/14+10/14 [Taking L.C.M within the denominators]

y+x =-11/14

Thus, we can say that x+y=y+x when x=5/7 and y= (-3/2)

If x+y=5 and x−y=2 what does (x−y)(x2−y2)?

So, with the system of equations:

x+y = 5

x-y=2

What you first want to do is find out what x and y are. The easiest way to do this is to set both equations equal to x, which will give you:

x=5-y

x=2+y

Then, you can just substitute x for one of the expressions in order to set them both equal to each other as such:

2+y=5-y

Now you can simply solve for y:

2+2y=5

2y=3

y=3/2

Then, plug y into either one of the original

Thanks.

What is the value of xy if 2x+y=10?

With this much amount of information given, x and y could be a lot of different numbers. For example, x and y could be 5 and so (2*5) +5 = 10 or x could be 4 and y could be 2 and so (2*4) +2 = 10.

To find the solution, either another formula, relating to this, must be given. Then, you can solve it by using simultaneous equations. If it is a word problem, then you must be able to create another equation with the information given or there is a totally different way of approaching the problem.

Don’t give up! Keep on trying to find the solution! Good Luck!

What will be the remainder of (5m+1)(5m+3)(5m+4)/5?

(5m+1)≡1mod(5)

(5m+3)≡3mod(5)

(5m+4)≡4mod(5)

⇒(5m+1)(5m+3)(5m+4)≡(1)(3)(4)mod(5)

⇒(5m+1)(5m+3)(5m+4)≡12mod(5)

⇒(5m+1)(5m+3)(5m+4)≡2mod(5)

If 1/3 of a number is 6 more than 3/5 of the number, what is 1/4 of the number?

The only tricky part is writing down this as an equation:

1/3 * x = 3/5 * x + 6

Then you just solve it:

(1/3 - 3/5) x = 6

(5/15 - 9/15) x = 6

(-4/15)x = 6

x = -90/4 = -22.5

1/4 of

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