Ifx, and X, are the roots of 15x2 + 28x + 12 = 0, then
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Answered by
5
Answer:
15x²+28x+12 =0
15x²+10x+18x+12=0
5x(3x+2)+6(3x+2)=0
(3x+2)(5x+6) =0
x= -2/3 , -6/5
:.x = -2/3 ,X= -6/5
Answered by
10
Answer:
Both cot-1 X1 and cot-1 X2 are real.
Step-by-step explanation:
there will be 2 answers
X1= -2/3. X2=-6/5
hence, both cot inverse x1. and cot inverse x2 are real
pls mark me as brainleast I have given 3 minutes of my life for this answer
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