Ifx=b
Cas A-sinA
and y=a Cos A + b Sim A, then prove that x2+y2=a2+b2
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LHS
X=bcosA-asinA
x^2=(bcosA-asinA)^2
=b^2cos^2A+a^2sin^2A-2abcosAsinA
y=acosA+bsinA
y^2=a^2cos^2A+b^2sin^2A+2abcosAsinA
x^2+y^2=a^2cos^2A+b^2cos^2A+a^2sin^2A+b^2sin^2A
=cos^2A(a^2+b^2)+sin^2A(a^2+b^2)
=(sin^2A+cos^2A)(a^2+b^2)
=a^2+b^2 (proved)
we know that
- sin^2A+cos^2A=1
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