Ifx- cos + r sin @
= 0 and y-sin 0-rcos @ = 0 then
2),
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Answer:
x
2
+y
2
−z
2
(xsinθ+ycosθ)
2
=z
2
x
2
sin
2
θ+y
2
cos
2
θ+2xysinθcosθ=z
2
...(1)
(xsinθ−ycosθ)
2
=x
2
sin
2
θ+y
2
cos
2
θ−2xysinθcosθ
=x
2
(1−cos
2
θ)+y
2
(1−sin
2
θ)−2xysinθcosθ
=x
2
+y
2
−x
2
cos
2
θ−y
2
sin
2
θ−2xysinθcosθ
=x
2
+y
2
−(x
2
cos
2
θ+y
2
sin
2
θ+2xysinθcosθ)
=x
2
+y
2
−z
2
Step-by-step explanation:
hope it will help you
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