Question

ifx+root2 is a factor of kx2-root2x+1 , then the value of k is

Answer 1

Answer:

given factor is x+√2

= x= -√2

f(x) = kx²-√2x +1

f(-√2)= k(-√2)² -√2(-√2)+1

2k+2+1=0

= 2k+3= 0

= 2k= -3

k= -3/2