Question

Ifx+y=11andxy=24thenx²+y²isequalto​

Answer 1

$x + y = 11 \\ = >( x + y)^{2} = 11 ^{2} \\ = > {x}^{2} + {y}^{2} + 2xy = 121 \\ = > {x}^{2} + {y}^{2} = 121 - 48 \\ {x}^{2} + {y}^{2} = 63$
please mark my answer as brainliest please please please please

Answer 2

$\huge{\mathcal{\underline{\green{SOLUTION}}}}$

${x}^{2} + {y}^{2} = {(x + y)}^{2} - 2xy = {11}^{2} - 2 \times 24 = 121 - 48 = 73$

$</p><p></p><p>\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}$