Question

ifx+y=12 and xy=14 then find the value of (x^2+y^2)​

Answer 1

x+y=12 and xy=14

Step-by-step explanation:

using the identity (a+b)²=a²+b²+2ab

(x+y)²=x²+y²+2ab

12²=x²+y²+2*14

144=x²+y²+28

x²+y²=144-28

X²+y²=116

Hope it helps ☺️