Question

Ifx+y=12 and xy = 32, find the value of x²+y²​

Answer 1

Answer:

solution, x+y=12

x²+y²=(x+y)-2xy

=12-2×32

=12-64

=-52

Answer 2

Answer:

Given that: x+y=12 and xy = 32

Using the identity, (x+y)

2

= x

2

+2xy+y

2

⇒ (12)

2

=x

2

+64+y

2

⇒ 144 = x

2

+y

2

+64

⇒ 144−64 = x

2

+y

2

⇒ 80 = x

2

+y

2

The answer is x

2

+y

2

= 80