Question

ifx=y-3,find the value of y from the equation y-(x-y/3)=4/5 (y-x)

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Answer 1

Answer:

y=7/5

Step-by-step explanation:

x=y-3

substituting it in the equation,

y-{[y-3-y]/3}=4/5(y-y-3)

y-(-3/3)=4/5(3)

y-(-1)=12/5

y+1=12/5

y=12/5-1

y=7/5

Answer 2

Answer:

Required value of y is $1 \frac{2}{5}$

Step-by-step explanation:

Given,

$x = y - 3$

Here we want to find value of y

It is also given,

$y - \frac{x - y}{3} = \frac{4}{5} (y - x) \\ \frac{3y - (x - y)}{3} = \frac{4(y - x)}{5} \\ \frac{3y - x + y}{3} = \frac{4y - 4x}{5}$

By cross multiplication,

$5 \times (3y - x + y) = 3 \times (4y - 4x) \\ 5 \times (4y - x) = 3 \times (4y - 4x) \\ 20y - 5x = 12y - 12x \\ 12x - 5x = 12y - 20y \\ 7x = - 8y.....(1)$

We are putting value

$x = y - 3$

So,

$7(y - 3) = - 8y \\ 7y - 21 = - 8y \\ 7y + 8y = 21 \\ 15y = 21 \\ y = \frac{21}{15} \\ y = \frac{7}{5} \\ y = 1 \frac{2}{5}$

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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2) https://brainly.in/question/1169549

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