. Ifx: y = 6:11. find (8x - 3y): (3x + 2y)
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Answer:
given
x:y=6:11
x= 6k , y= 11k , where k is a constant.
there fore,
(8x- 3y) :(3x+ 2y)= (8 × 6k - 3 × 11 k ):
(3 × 6k + 2 × 11k)
= 15k : 40k
= 3 : 8
hence , this is the required ratio.
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