Question

ifx+y=6, y+z=7 and z+x=9 the average of x y and z is​

Answer 1

Now.....

$= > {(x + y) + (y + z) + (z + x)} =6 + 7 + 9 + \\ = > 2(x + y + z) = 22 \\ = > x + y + z = 11$

Answer 2

Answer:

x+y=6

y+z=7

z+x=9

(x+y)+(y+z)+(z+x)=6+7+9

x+y+y+z+z+x=22

2x+2y+2z=22

2(x+y+z)=22

x+y+z=22/2

x+y+z=11