ifx+y+z=0 then write the value of x^3+y^3+8 please anyone give me it's solution
anandtiwari0019:
oo
its easy
that what i thought where is z in this equation
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Answered by
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heya . here is your answer
x+y+z=0
x^3+y^3+8 = x+y+2
=6xy
x+y+z=0
x^3+y^3+8 = x+y+2
=6xy
Answered by
6
Hey bro
Given => x + y + 2 = 0
To find => x³ + y³ + 8
= (x)³ + (y)³ + (2)³
Let a = x , b = y , c = 2
We know that when ( a + b + c ) = 0 then
a³ + b³ + c³ = 3abc
Here ( x + y + 2 ) = 0
So x³ + y³ + 8 = 3 ( x ) ( y ) ( 2 )
= 6xy
Given => x + y + 2 = 0
To find => x³ + y³ + 8
= (x)³ + (y)³ + (2)³
Let a = x , b = y , c = 2
We know that when ( a + b + c ) = 0 then
a³ + b³ + c³ = 3abc
Here ( x + y + 2 ) = 0
So x³ + y³ + 8 = 3 ( x ) ( y ) ( 2 )
= 6xy
Please bro mark my answer as the BRAINLLIEST ANSWER
Thanks bro
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