ifx2+y2=25xyprove that 2log (x-y)=log23+logxlogy
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x² + y² = 25xy
(x - y)² +2xy = 25xy
(x - y)² = 23xy
take log both sides ,
log(x -y)² = log(23xy)
2log(x - y) = log23 + logx + logy
2log(x -y) = log23 + logx + logy
2log(x - y) = log23 + Iogx + logy
log( x - y) = 1/2{ log23 + logx + logy }
here something typing mistake ,
I think question is
if x² + y² = 25xy
then , proved that
log(x - y) = 1/2{log23 + logx + logy }
(x - y)² +2xy = 25xy
(x - y)² = 23xy
take log both sides ,
log(x -y)² = log(23xy)
2log(x - y) = log23 + logx + logy
2log(x -y) = log23 + logx + logy
2log(x - y) = log23 + Iogx + logy
log( x - y) = 1/2{ log23 + logx + logy }
here something typing mistake ,
I think question is
if x² + y² = 25xy
then , proved that
log(x - y) = 1/2{log23 + logx + logy }
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