Question

ifx3 is one rooting of the square are of x2-2kx-6=0 then find the value of x

Answer 1

♧♧HERE IS YOUR ANSWER♧♧

Since x = 3 is a root of x² - 2kx - 6 = 0, x = 3 satisfies the equation.

So, the value of k is 1/2.

3² - (2×k×3) - 6 = 0

or, 9 - 6k - 6 = 0

or, 6k = 3

or, k = 1/2

So the value of k = 1/2

♧♧HOPE IT HELPS YOU♧♧