Question

Ify = (x3 + x2 +x+1) dx then find
dy
dx​

Answer 1

Step-by-step explanation:

We have, y=x

x

Taking log on both the sides, we get

logy=xlogx

On differentiating w.r.t. x, we get

y

1

dx

dy

=

x

x

+logx

⇒

dx

dy

=y+ylogx

⇒

dx

dy

=x

x

(1+logx) ....(∵y=x

x

)

Answer 2

Step-by-step explanation:

Given

y=(x^3+x^2+x+1)dx

To find÷dy

dx

first step÷

y=dx(x^3+x^2+x+1)

y=dx^4+dx^3+dx^2+dx

y=dx^10

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