Question

ig., AD and CF are respectively perpendiculars to sides BC and AB of △ABC. If ∠FCD = 500, find ∠BAD. ​

Answer 1

Answer:We know that the sum of all angles of a triangle is 180°

Therefore, for the given △FCB, we have

∠FCB + ∠CBF + ∠BFC = 180°

50° + ∠CBF + 90° = 180°

∠CBF = 180° – 50° – 90° = 40°

Using the above steps for △ABD, we can say that:

∠ABD + ∠BDA + ∠BAD = 180°

∠BAD = 180° – 90° – 40° = 50°

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