ig tanA+ cot A=3 , find the value of tan^2+cot^2A
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Given:
- tanA + cotA = 3
To find:
- tan²A + cot²A = ?
Solution:
We are given the Relation between tan A and cot A that:
tan A + cot A = 3
Squaring on both sides,
(tan A + cot A)² = 3²
Split using (a + b)² = a² + b² + 2ab
tan²A + cot²A + 2 tanAcotA = 9
tanAcotA can be written as 1 since they are reciprocals to each other.
⇒ tan²A + cot²A + 2(1) = 9
⇒ tan²A + cot²A + 2 = 9
⇒ tan²A + cot²A = 9 - 2
⇒ tan²A + cot²A = 7
∴ tan²A + cot²A = 7
KNOW MORE:
- sin and cosec are reciprocals to each other.
- cos and sec are reciprocals to each other.
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