Igcse physics mcq bullet of mass 0.10 kg travels horizontally at a speed of 600 m/s. It strikes a stationary wooden block of mass 1.90 kg resting on a frictionless, horizontal surface. The bullet stays in the block. What is the speed of the bullet and the block immediately after the impact?
Answers
Answered by
4
By conservation of moventum laws
V = 0.1*600/(0.1+1.9)=60/2=30m/s
V = 0.1*600/(0.1+1.9)=60/2=30m/s
rishi7586:
hii please brainlist
Similar questions