Physics, asked by BrainlyHelper, 1 year ago

ight is incident from glass (μ= 1.5) to air. Sketch the variation of the angle of deviation 5 with the angle of incident i for 0 < i < 90°.

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Answered by Anky62
1
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Answered by prmkulk1978
2

Given :

μ= 1.5 (air)

given 0 < i < 90°

Let c be the critical angle

sin c/ sin r= μa/μg

sin c/ sin 90=1/1.5= 0.66

c= 40°48'

The angle of deviation due to refraction from glass to air increases  as the angle of incidence increases from 0° to 40° 48'

The angle of deviation due to internal reflection further increases for 40° 48' to 45 ° and then decreases.

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