ight is incident from glass (μ= 1.5) to air. Sketch the variation of the angle of deviation 5 with the angle of incident i for 0 < i < 90°.
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Given :
μ= 1.5 (air)
given 0 < i < 90°
Let c be the critical angle
sin c/ sin r= μa/μg
sin c/ sin 90=1/1.5= 0.66
c= 40°48'
The angle of deviation due to refraction from glass to air increases as the angle of incidence increases from 0° to 40° 48'
The angle of deviation due to internal reflection further increases for 40° 48' to 45 ° and then decreases.
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