Ih a normal trapezium.
b) What will be the length of non
parallel sides of an isosceles trapezium if its
Perimeter is 42 cm and parallel sides are 10
cm and
13 cm?
Answers
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Step-by-step explanation:
Let the parallel sides of trapezium be 'a' and 'b' and the distance between them i.e. the height of trapezium be 'h'.
Therefore area of trapezium is given by
=1/2 *(sum of parallel side)*(distance between parallel side i.e. height of trapezium) ……(1)
Now take 'a'=12 & 'b'=8 …. (Sides are given)
Therefore,
Sum of parallel sides=a+b=12+8…. (2)
Sum of parallel side=20cm
Area=60 cm^2 …..(given) …..(3)
Putting (2) & (3) in (1) we get,
60=1/2 * 20*h
h=60/10
h=6cm
Therefore height of trapezium is 6cm.
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