Question

IH.. elevation in boiling point of
27. For CrС13.XNH3, elevation in bo
1 molal solution is double of 1 molal se
glucose; hence X is, if complex is 100% io
(2) 5
(3) 6
(4) 3
(1) 4
.
.
.​

Answer 1

Answer:

option 1 is correct

Because that will be 2 pi bonds,  pi-bond and  pi-bond

so overall 4  

Answer 2

The value of x should be equal to 4.

• Elevation in boiling point of a solution is equal to i×Kb×m.
• Since Kb and m are same for both solutions , i(crCl3.XNH3) should be double of i(glucose).
• i(CrCl3.XNH3)=2; this means that the complex dissociates into two ions , so one of the cl- must be outside the coordination sphere.
• Cr here forms an octahedral complex with 2 Cl inside and 1 Cl outside the coordination sphere so, there must be 4 NH3 present.