Question

(ii) 1/7(3x – 5)^2 = 28​

Answer 1

Step-by-step explanation:

7

1

(3x−5)

2

=28

Simplifying the equation,

⇒(3x−5)

2

=28×7

⇒(3x−5)

2

=196

⇒9x

2

−30x+25=196

⇒9x

2

−30x+25−196=0

⇒9x

2

−30x−171=0

Dividing the whole equation by 3, we get

⇒3x

2

−10x−57=0

⇒3x

2

−19x+9x−57=0

⇒x(3x−19)+3(3x−19)=0

⇒(x+3)(3x−19)=0

⇒(x+3)=0 or (3x−19)=0

⇒x=−3 or 3x=19

⇒x=−3 or x=

3

19

∴ Value of x=−3,

3

19

Answer 2

Answer:

1/7(3x - 5) ^2 = 28

(3x - 5)^2 = 196

3x - 5 = +- 14

when;

3x - 5 = -14 3x - 5 = 14

3x = -9 3x = 19

x = 9 x = 19/3