(ii)
1
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Answers
Answered by
1
Answer:
x^3-4x^2-7x+10
let x=1
(1)^3-4(1)^2-7(1)+10
1-4-7+10=0
so, (x-1) is a factor.
now divide x^3-4x^2-7x-10 from (x-1)=x^2-3x-10
then by spliting the middle term
x^2-3x-10
x^2-5x+2x-10
x(x-5)+2(x-5)
(x+2)(x-5)
factors are (x-1) (x+2) (x-5)
Answered by
0
Answer:
can't understand the question from your side
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