Question

(ii) 10p2q2 – 21pq + 9​

Answer 1

I hope its help u ...

yrr

Answer 2

In /triangle ABC∆ABC

The bisector of <A intersects BC in D

And

.AB=18cm

.AC=15cm

.BC=22cm

BD ?

solve

In ∆ABC,AD is the bisector of <A

/frac{AB}{AC}=\frac{BD}{DC}

AC

AB

=

DC

BD

(The external bisector of angle of a triangle divide the opposite side externally in the ratio of the sides containing the angle)

/frac{AB}{AC}=/frac{BD}{(BC-BD)}

AC

AB

=

(BC-BD)

BD

=>/frac{6}{5}=/frac(BD){(22-BD)}

5

6

=(22-BD)

BD