Question

சுருக்குக

"(ii) " (10x^3-25x^2+4x-10)/(-4-10x^2 )

Answer 1

Answer:

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Answer 2

$-x+\frac{5}{2}$

விளக்குக:

$\frac{10 x^{3}-25 x^{2}+4 x-10}{-4-10 x^{2}}$

$=\frac{5 x^{2}[2 x-5]+2[2 x-5]}{-2\left[5 x^{2}+2\right]}$

$=\frac{[2 x-5]\left[5 x^{2}+2\right]}{-2\left[5 x^{2}+2\right]}$

$=\frac{[2 x-5]}{-2}$

$=\frac{2 x}{-2}-\frac{5}{-2}$

$=-x+\frac{5}{2}$

$\frac{10 x^{3}-25 x^{2}+4 x-10}{-4-10 x^{2}}$ என்ற விகிதமுறு கோவையின் எளிய

வடிவம் = $-x+\frac{5}{2}$