(ii)
- 12x + 22x2 - 16x} + 4 by 2x
Answers
Answer:
0-(12*x^(5)-x^(4)-42*x^(3)+27*x^(2)+16*x-12)=0
Step-by-step explanation:
0-((((((12•(x5))-(x4))-(42•(x3)))+33x2)+16x)-12) = 0
0-((((((12•(x5))-(x4))-(2•3•7x3))+33x2)+16x)-12) = 0
0-((((((22•3x5)-x4)-(2•3•7x3))+33x2)+16x)-12) = 0
Factoring: -12x5+x4+42x3-27x2-16x+12
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: x4-27x2
Group 2: -12x5+42x3
Group 3: -16x+12
Pull out from each group separately :
Group 1: (x2-27) • (x2)
Group 2: (2x2-7) • (-6x3)
Group 3: (4x-3) • (-4)
Looking for common sub-expressions :
Group 1: (x2-27) • (x2)
Group 3: (4x-3) • (-4)
Group 2: (2x2-7) • (-6x3)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication