Question

II
- 2 / - (0-2 Po
U
II
-
0.083
(0.10-0.083)X -e-(0.10-0.083)x 20
20]
0.10
= -0.83[0 - 0.7117] = 0.59 = 59%
Prob.10. In a tool crib manned by a single assistant,
operators arrive at the tool crib at the rate of 10 per hour. Each
operator needs 3 minutes on an average to be served. Find out
the loss of production due to waiting of an operator in a shift of 8
hours if rate of production is 100 units per shift.
.
Soln. Given : a = 10 operators / hour
1
U = operator/minute
3
.: M = 20 operator / hour.​

Answer 1

$75 + 45 = 120$

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