ii) 2 sec 0 – sect 0 – 2 cosec2 0 + cosec4 0 = cott 0 – tant e.
ca 1+ cose – sino
... tan? 0-1 - ser2
- cot A
()
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Answer:
LHS :
2sec 2 θ−sec 4 θ−2cosec 2 θ+cosec 4 θ
=(cosec 4 θ−2cosec 2 θ)−(sec 4 θ−2sec 2 θ)
=(cosec 4 θ−2cosec 2 θ+1)−(sec 4 θ−2sec 2 θ+1)
=(cosec 2 θ−1) 2 −(sec 2 θ−1)2
=cot 4 θ−tan 4 θ
= RHS
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