Math, asked by adeshkumar85, 11 months ago

ii) 2 sec 0 – sect 0 – 2 cosec2 0 + cosec4 0 = cott 0 – tant e.
ca 1+ cose – sino
... tan? 0-1 - ser2
- cot A
()​

Answers

Answered by Anonymous
12

Answer:

LHS :

2sec  2 θ−sec  4 θ−2cosec  2 θ+cosec  4 θ

=(cosec  4 θ−2cosec  2 θ)−(sec  4 θ−2sec  2 θ)

=(cosec  4 θ−2cosec  2 θ+1)−(sec  4 θ−2sec  2 θ+1)

=(cosec  2 θ−1) 2 −(sec  2 θ−1)2

 =cot  4 θ−tan  4 θ

= RHS

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