Math, asked by kamblesanju, 3 months ago

(ii) 2 years ago, my age was 4 times the age of my son then. 6 years ago, my age
was twice the square of the age of my son then. Find the present age of my son.​

Answers

Answered by KrishnaJha5
1

Answer:

The present age of my son is 10 years.

It is given that my age was twice the square of the age of my son. y = 4.25 is discarded as age cannot be fractional. So, present age of son is y = 10 years.

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