Question

(ii) (2a’ – 3bʻ), (2a3 +3b"), (2a4 – 3a²b2 + b4)​

Answer 1

Answer:

2a−[4b−4a−(3b−

2a+2b

ˉ

)]

2a−[4b−4a−(3b−2(a+b))]

2a−[4b−4a−(3b−2a−2b)]

2a−[4b−4a−(b−2a)]

2a−[4b−4a−b+2a)]

2a−[4b−6a−b)]

2a−[4b−6a+b]

2a−[5b−6a]

2a−5b+6a

8a−5b

HOPE THIS WILL HELP U DEAR...