Question

(ii)2p^(2)+5p-3=0 , p=(1)/(2) ,-3 ans
$2p ^{2} + 5p - 3 = 0 , p = (1) /(2), -3$
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Answer 1

Answer:

Step-by-step explanation:

L.H.S. = 2(1)2 + 5(1) – 3

= 2(1) + 5 – 3

= 2 + 5 – 3

= 7 – 3

= 4

≠ R.H.S.

∴ L.H.S. ≠ R.H.S.

Thus equation is not satisfied.

By putting p = ½ in L.H.S. we get

L.H.S. = 2( ½)2 +5( ½ ) – 3

= 2( ¼ )  + 5/2 – 3

= ½ + 5/2 – 3

= (1+5)/2 – 3

= 6/2 – 3

= 3 – 3

= 0

= R.H.S.

∴ L.H.S. = R.H.S.

Thus equation is satisfied.

So, ½, is the root of the given quadratic equation.

c) By putting p = – 3 in L.H.S. we get

L.H.S. = 2(– 3)2 + 5(– 3) – 3

= 2(9) – 15 – 3

= 18 – 18

= 0

= R.H.S.

∴ L.H.S. = R.H.S.

Thus equation is satisfied.So, ½, is the root of the given quadratic equation.

c) By putting p = – 3 in L.H.S. we get

L.H.S. = 2(– 3)2 + 5(– 3) – 3

= 2(9) – 15 – 3

= 18 – 18

= 0

= R.H.S.

∴ L.H.S. = R.H.S.

Thus equation is satisfied.

So,  – 3 is the root of the given quadratic equation.

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