Math, asked by Ssesighqnfr, 6 months ago

(ii) (2x - 1) (2x + 1)(4x² +1) (16x⁴+1)
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Answers

Answered by Bhawana861
1

Answer:

Step-by-step explanation:

ii. (2x-1)(2x+1)(4x^2+1)(16x^4+1)

= (2x^2 - 1^2)(4x^2+1)(16x^4+1)

= (4x^2-1)(4x^2+1)(16x^4+1)

= {(4x^2)^2-1^2}(16x^4+1)

= (16x^2-1)(16x^4+1)

= (16x^2)^2 - 1^2

=(256x^4 - 1) answer

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