Question

(ii) √2x + 8 + √x+ 5 = 7​

Answer 1

Answer:

$\sqrt{2}x + \sqrt{x} = 7 - 8 - 5 \\ \sqrt{2x} + \sqrt{x} = - 6 \\ ( \sqrt{2x} + \sqrt{x) ^{2} } = ( - 6) ^{2} \\ 2x + 2 \times \sqrt{2x} \times \sqrt{x} + x = 36 \\ 3x + 2 \sqrt{2x ^{2} } = 36 \\ 3x + 2x \sqrt{2} = 36 \\ 2x \sqrt{2} = 36 - 3x \\ 2x = \frac{36 - 3x}{\sqrt{2} } \\ x = \frac{36 - 3x}{2 \sqrt{2} }$