Question

ii) 34+32+30+..+10 find sum of all terms ​

Answer 1

Answer:

a=34.

a2=32

d=-2

an=10

an=a+(n-1)d

10=34+(n-1)-2

10-34=(n-1)-2

-24=(n-1)-2

12=n-1

so, n= 13

sn = n/2(2a+(n-1)d)

sn = 13/2(2*34+(13-1)-2)

sn = 13/2(68+12* -2)

sn = 13/2(80* -2)

sn = 13/2(-160)

sn =13* -80

sn = -1040

so, sum of all term is 1040.

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