Math, asked by divyasahithigorusu, 7 months ago

(ii) (3x - 2y) (4x + 3y) (8x - 5y).​

Answers

Answered by kmpsujipavi
2

Answer:

= (12x2 + xy – 6y2) (8x – 5y) {from (i)}

= 8x (12x2 + xy – 6y2) – 5y (12y2 + xy – 6y2)

= 96x3 + 8x2y – 48xy2 – 60x2y – 5xy2 + 30y3

= 96x3 + 8x2y – 60x2y – 48xy2 – 5xy2 + 30y3

= 96x3 – 52x2y – 53xy2 + 30y3

Answered by suprabhapurvey
3

Step-by-step explanation:

(3x - 2y)(4x + 3y)(8x - 5y) \\ (3x)(4x + 3y)( - 2y)(4x + 3y)(8x - 5y) \\ 12 {x}^{2}  + 9xy - 8xy - 6 {y}^{2} (8x - 5y) \\ 12 {x}^{2} + xy - 6 {y}^{2} (8x - 5y)  \\ 12 {x}^{2} (8x - 5y) + xy(8x - 5y) - 6 {y}^{2} (8x - 5y) \\ 48 {x}^{3}  - 60 {x}^{2}y + 8 {x}^{2}y - 5x {y}^{2}    - 48x {y}^{2}  + 30 {y}^{3}  \\ 48 {x}^{3}  - 52 {x}^{2}y - 53x {y}^{2}   + 30 {y}^{3}

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