Math, asked by mankekaja, 3 months ago

(ii) 3y² - 6 - 2y + y² - 3y + 7 - y² - 4y - Y²+5​

Answers

Answered by abhishekshibu9267
1

Answer:

3y^2 - 6 - 2y + y^2 - 3y + 7 - y^2 - 4y - Y^2+5\\\\2y^2 - 9y +6\\

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Answered by aditya1222415364
1

Answer:

y = 9 + 33 ÷ 4 (or ) 9 - 33 ÷ 4

Step-by-step explanation:

= 3y² - 6 - 2y + - 3y + 7 - - 4y - + 5

= 3y² + - - - 2y - 3y - 4y - 6 + 7 + 5

= 4y² - 2y² - 9y + 6

= 2y² - 9y + 6

b = -9 a = 2 c = 6

- 4ac = 81 - 4(2)(6)

= 81 - 48

= 33

y =  \frac{9 +  \sqrt{33} }{4}

( or )

y =  \frac{9 -  \sqrt{33} }{4}

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